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Given an array of integers nums sorted in ascending order, find the starting and ending position of a given target value. Your algorithm's runtime complexity must be in the order of O(log n).

If the target is not found in the array, return [-1, -1].

Example 1:

Input: nums = [5,7,7,8,8,10], target = 8
Output: [3,4]

Example 2:

Input: nums = [5,7,7,8,8,10], target = 6
Output: [-1,-1]

Solution in C++

class Solution {
public:
    vector<int> searchRange(vector<int>& nums, int target) {
        vector<int> r={-1,-1};

        int n=nums.size();
        for(int i=0; i<n; i++) {
                if (r[0]<0) {
                        if (nums[i]==target) r[0]=r[1]=i;
                }
                else if (nums[i]!=target) break;
                else r[1]=i;
        }
        
        return r;
    }
};